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By “low side”, you’re referring to the inverting inputs of the comparators. You should fix the capitalisation of sentences and electrical units ‘F’ for farad to improve legibility and credibility.
I’m not following you. It sounds like you’re trying to drive this circuit with a signal that includes a considerable DC bias, which explains why all of the LEDs light up right away when you remove short out the capacitor. Setting 7 higher than ground biases the low side of the comparators, allowing them to turn on with a lower output from the amp.
To be clear, removing the capacitor doesn’t light up the LEDs all at once. Pin 7 is the output of the internal amplifier, and pin 8 is its input, designed to accept a low-level AC input 57 mV for a 0-dB indication.
Passing Vin through a reverse capacitor seems to be potentially more prone to failure.
5+1 led vu-meter with AN6884
I know the correct names, but I conversely find “inverting” and “noninverting” confusing when dealing with comparators, since those terms make more sense when dealing with op-amps. The LED pins connect to the negative side of the LEDs, and the pins go low when the output of the internal amp goes above Vref dropped by voltage dividing resistors at each comparator. Placing it at a higher voltage within the datasheet’s max specified V will both lower the amplification and raise the lower rail of the comparators in the block diagram.
You might want to edit to explain your answer a bit more. Have you tried a non-polarized capacitor e. Capacitor with polarity can be used ac couple or blocking. Your description doesn’t agree with that in the datasheet. Per AN’d datasheet. Right, I get that pin 7 is the output of the amp, but it’s part of the negative feedback loop on the amp.
Per AN’d datasheetPin 8 is the signal input pin, and it’s the internal Op amp’s positive input.
AN 데이터시트(PDF) – Panasonic Semiconductor
There is also no discharge path with your arrangement. It just shortens the range of turn over which the potentiometer works.
That is to say that the LEDs all come on at a much smaller turn of the potentiometer. Indeed, it must in order for any of the LEDs to turn on! I am looking at the test circuits on the ann6884 sheet for the AN VU meter IC, and Datasheft cannot understand the connection to pin 8 in the following diagram: This makes sense, but why not a diode? Reverse biased capacitor on IC input pin Ask Question.
I’m not reading it that way. That means there is a small current flow out from the pin. Pin 8 accepts a positive input voltage. Vref is the high side of the 5 LED comparators in the datasheet block diagram. This circuit will light the LEDs as the input voltage on pin 8 increases relative to pin 7.
However, if that’s the case, I can’t explain why reversing the capacitor doesn’t work, unless the actual polarity of the capacitor is backwards from what you think it is. If I “correct” the orientation, the circuit does not work at all. Most people use “low” to refer to either a lower voltage, or a lower position on the diagram. Email Required, but never shown.
AN Datasheet(PDF) – Panasonic Semiconductor
So it determines the DC bias of the block capacitor’s polarity. Home Questions Tags Users Unanswered. Sign up or log in Datashete up using Google. It appears to be reversed.
(PDF) AN6884 Datasheet download
That’s clear, because the input in my test circuit is DC. Very confusing terminology, since the inverting input can have a higher voltage than the noninverting input.
Sign up using Facebook. How does doing anything to pin 7 or pin 8 affect that?